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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    Given   the   following   thermochemical equations: \[Zn+\frac{1}{2}{{O}_{2}}\xrightarrow[{}]{{}}ZnO+84,000\,cal\] \[Hg+\frac{1}{2}{{O}_{2}}\xrightarrow[{}]{{}}HgO+21,700\,cal\] Accordingly the heat of reaction for the following reaction, \[Zn+HgO\xrightarrow[{}]{{}}Hg+\]heat is:

    A)  105, 700 cal    

    B)         61, 000 cal

    C)  105, 000 cal    

    D)         60, 000 cal

    E)  62, 300 cal

    Correct Answer: E

    Solution :

    \[Zn\xrightarrow{{}}ZnO+84,000\,cal\] \[\begin{align}   & \underline{HgO\xrightarrow{{}}Hg+(84,000-21,700)cal\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\  & Zn+HgO\xrightarrow{{}}ZnO+Hg+(84,000-21,700)cal \\ \end{align}\] So, heat of formation of the reaction \[Zn+HgO\xrightarrow{{}}Hg,\]is \[=(84,000-21,700)\text{ }cal\] \[=62300\text{ }cal\]


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