A) \[205\,\Omega \]
B) \[10\,\Omega \]
C) \[3.5\,\Omega \]
D) \[5\,\Omega \]
E) \[3\,\Omega \]
Correct Answer: D
Solution :
Net resistance of\[3\,\Omega \]and\[7\,\Omega \]resistors (in series) \[R=3+7=10\,\Omega \] R and\[10\,\Omega \]are in parallel, so \[R\,=\frac{10\times 10}{10+10}=5\,\Omega \] \[R\,\]and\[5\,\Omega \]are in series, so \[R\,\,=5+5=10\,\Omega \] Now,\[R\,\]and\[10\,\Omega \]are in parallel, so \[R\,=\frac{10\times 10}{10+10}=5\,\Omega \]
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