CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    A particle moves along Y-axis in such a way that its y-coordinate varies with time t according to the relation\[y=3+5t+7{{t}^{2}}\]. The initial velocity and acceleration of the particle are respectively:

    A)  \[14m{{s}^{-1}},\text{ }-5m{{s}^{-2}}\]

    B)  \[19m{{s}^{-1}},-9m{{s}^{-2}}\]

    C)  \[-14m{{s}^{-1}},-5m{{s}^{-2}}\]

    D)  \[3m{{s}^{-1}},-5m{{s}^{-2}}\]

    E)  \[5m{{s}^{-1}},14m{{s}^{-2}}\]

    Correct Answer: E

    Solution :

    \[v=\frac{dy}{dt}=0+5+14t\] At        \[t=0,\text{ }{{v}_{0}}=5\text{ }m/s\]                 \[a=\frac{dv}{dt}=0+14=14m/{{s}^{2}}\]


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