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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    The coefficient of\[x\]in\[{{x}^{2}}+px+q=0\]was taken as 17 in place of 13 and its roots were found to be\[-2\]and\[-15\]The roots of the original equation are:

    A)  3, 7                       

    B)         \[-3,7\]

    C)  \[-3,-7\]             

    D)         \[3,10\]

    E)  \[-3,-10\]

    Correct Answer: E

    Solution :

    The given equation is \[{{x}^{2}}+17x+q=0\] \[\therefore \]Product of roots\[=(-2)(-15)=q\] \[\Rightarrow \]               \[q=30\] \[\therefore \]Original equation is \[{{x}^{2}}+13x+30=0\] \[\Rightarrow \]               \[{{x}^{2}}+10x+3x+30=0\] \[\Rightarrow \]               \[(x+10)(x+3)=0\] \[\Rightarrow \]               \[x=-10,-3\]


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