CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    \[\sqrt{4},\sqrt[4]{4},\sqrt[8]{4},\sqrt[16]{4},....\]to\[\infty \]are roots of the equation:

    A)  \[{{x}^{2}}-4=0\]     

    B)         \[{{x}^{2}}-4x+6=0\]

    C)                         \[{{x}^{2}}-5x+4=0\]

    D)         \[{{x}^{2}}-3x+2=0\]

    E)  \[{{x}^{2}}-x=0\]

    Correct Answer: C

    Solution :

    \[{{4}^{1/2}},{{4}^{1/4}},{{4}^{1/8}},{{4}^{1/16}},.....\]are given roots, then Sum of roots                 \[={{4}^{1/2}}{{.4}^{1/4}}{{.4}^{1/8}},.....\] \[=5\] Product of roots                 \[={{4}^{1/2}}{{.4}^{1/4}}{{.4}^{1/8}}.....\]                 \[={{4}^{1/2+1/4+1/8+.....}}\]                 \[={{4}^{\frac{1/2}{1-1/2}}}=4\] \[\therefore \]Required equation is \[{{x}^{2}}\] (sum of roots) x + (product of roots) = 0 \[\Rightarrow \]               \[{{x}^{2}}-5x+4=0\]


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