A) \[a+b\]
B) \[a-b\]
C) \[{{a}^{2}}+{{c}^{2}}\]
D) \[{{a}^{2}}-{{b}^{2}}\]
E) \[{{a}^{3}}+{{b}^{3}}\]
Correct Answer: E
Solution :
\[\therefore \] \[xyz=(a\alpha +b\beta )(a+b)(a\beta +b\alpha )\] \[=(a+b)({{a}^{2}}\alpha \beta +ab{{a}^{2}}+ab{{\beta }^{2}}+{{b}^{2}}\alpha \beta )\] \[=(a+b)({{a}^{2}}-ab-{{b}^{2}})\] \[={{a}^{3}}+{{b}^{3}}\]
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