CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2003

  • question_answer
    A stationary body of mass m explodes into three parts having masses in the ratio 1 : 3 : 3. The two fractions with equal masses move at right angles to each other with a velocity of \[1.5\text{ }m{{s}^{-1}}\]Then the velocity of the third body is:

    A)  \[4.5\sqrt{2}m{{s}^{-1}}\]                          

    B)  \[5\,m{{s}^{-1}}\]          

    C)         \[5\sqrt{32}m{{s}^{-1}}\]     

    D)         \[1.5\,m{{s}^{-1}}\]

    E)  \[1\,m{{s}^{-1}}\]

    Correct Answer: A

    Solution :

    \[{{(1\times v)}^{2}}={{(3\times 1.5)}^{2}}+{{(3\times 1.5)}^{2}}\] \[\Rightarrow \]               \[v=4.5\sqrt{2}m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner