CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    A torque of 50 Nm acting on a wheel at rest rotates it through 200 rad in 5 s. Calculate the angular acceleration produced.

    A)  \[8\text{ }rad\text{ }{{s}^{-2}}\]              

    B) \[4\text{ }rad\text{ }{{s}^{-2}}\]               

    C)         \[\text{16 }rad\text{ }{{s}^{-2}}\]      

    D)        \[\text{12 }rad\text{ }{{s}^{-2}}\]

    E)  \[\text{10 }rad\text{ }{{s}^{-2}}\]

    Correct Answer: A

    Solution :

    \[\omega ={{\omega }_{0}}+\alpha t\] \[\Rightarrow \]               \[\frac{200}{5}=0+\alpha \times 5\] \[\Rightarrow \]               \[\alpha =\frac{200}{25}=8\,rad/{{s}^{2}}\]


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