A) Cannizaros reaction
B) Clemmensens reduction
C) Wolff-Kishner reduction
D) Meerwein-Pondorf reduction
E) Beckmann rearrangement
Correct Answer: C
Solution :
Reduction of carbonyl compound with hydrazine in presence of strong base is called Wolff-Kishner reduction. In this reduction alkanes are formed. \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,=O+{{H}_{2}}N.N{{H}_{2}}\xrightarrow[-{{H}_{2}}O]{{}}\] \[C{{H}_{3}}CH=N.N{{H}_{2}}\xrightarrow[glycol]{KOH,\,453-473\,K}\] \[C{{H}_{3}}.C{{H}_{3}}+{{N}_{2}}\]
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