A) \[{{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}C{{H}_{2}}Br\]
C) \[{{(C{{H}_{3}})}_{2}}C(Br)C{{H}_{2}}C{{H}_{3}}\]
D) \[C{{H}_{3}}CH(C{{H}_{3}})CH(Br)C{{H}_{2}}C{{H}_{3}}\]
E) \[C{{H}_{3}}CH(C{{H}_{3}})CH(Br)C{{H}_{2}}(Br)\]
Correct Answer: A
Solution :
The addition of HBr is according to Markownikoff s rule in this reaction. \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-CH=C{{H}_{2}}+\overset{+\,\,\,-}{\mathop{HBr}}\,\xrightarrow{{}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\]
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