question_answer

An open tank filled with water (density)\[\rho \]has a narrow hole at a depth of h below the water surface. The velocity of water flowing out is:

A)  \[hpg\]               

B)         \[2gh\]

C)  \[\sqrt{2gh}\]                  

D)         \[gh\]

E)  \[\sqrt{2gh\rho }\]

Correct Answer: C

Solution :

From Bernoullis theorem \[P+0+\rho gH=P+\frac{1}{2}\rho {{v}^{2}}+\rho g(H-h)\]                 \[\frac{1}{2}\rho {{v}^{2}}=\rho gh\] \[\Rightarrow \]               \[v=\sqrt{2gh}\]