A) \[\sqrt{2Rg}\]
B) \[\sqrt{Rg}\]
C) \[\sqrt{Rg/2}\]
D) \[\sqrt{Rg/4}\]
E) none of the above
Correct Answer: C
Solution :
Orbital velocity\[({{v}_{o}})\]at a height h above the earths surface is given by \[{{v}_{o}}={{R}_{e}}\sqrt{\frac{g}{{{R}_{e}}+h}}\] Given, \[h={{R}_{e}}\] \[\therefore \] \[{{v}_{o}}=R\sqrt{\frac{g}{2R}}=\sqrt{\frac{Rg}{2}}\]
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