CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    The vector equation \[\overrightarrow{r}=\hat{i}-2\hat{j}-\hat{k}+t(6\hat{j}-\hat{k})\] represents a straight line passing through the points:

    A)  \[(0,\text{ }6,-1)\]and\[(1,-2,-1)\]

    B)  \[(0,\text{ }6,-1)\]and\[(-1,-4,-2)\]

    C)  \[(1,-2,-1)\]and \[(1,4,-2)\]

    D)  \[(1,-2,-1)\]and \[(0,-6,1)\]

    E)  \[(1,4,-2)\]and\[(2,10,-3)\]

    Correct Answer: C

    Solution :

    Equation of line passing through\[\overrightarrow{a}\]and\[\overrightarrow{b}\]is \[\overrightarrow{a}+\lambda (\overrightarrow{b}-\overrightarrow{a})\] \[\Rightarrow \]               \[\overrightarrow{b}-\overrightarrow{a}=6\overrightarrow{j}-\vec{k}\] \[\Rightarrow \]               \[\overrightarrow{b}=6\overrightarrow{j}-\overrightarrow{k}+\hat{i}-2\hat{j}-\hat{k}\]                 \[=\hat{i}+4\hat{j}-2\hat{k}\] \[\therefore \]Given line passes through\[(1,-2,-1)\]and\[(1,4,-2)\].


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