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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    The length of the tangent from (5, 1) to the circle \[{{x}^{2}}\text{+ }{{y}^{2}}+6x-4y-3=0\]is:

    A)  81                                         

    B)  49                         

    C)  63                         

    D)         21

    E)  7

    Correct Answer: E

    Solution :

    Required length of tangent is\[\sqrt{{{S}_{1}}},\]where \[{{S}_{1}}=25+1+30-4-3=49\] \[\therefore \]  \[\sqrt{{{S}_{1}}}=7\]


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