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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    Distance between the pair of parallel lines \[{{x}^{2}}+2\sqrt{2}xy+2{{y}^{2}}+4x+4\sqrt{2}y-8=0\]

    A)  \[\frac{4\sqrt{3}}{3}\]

    B)                         \[2\sqrt{2}\]

    C)  \[4\sqrt{2}\]     

    D)         \[8\]

    E)  \[4\]

    Correct Answer: E

    Solution :

    Given pair of lines is \[{{x}^{2}}+2\sqrt{2}xy+2{{y}^{2}}+4x+4\sqrt{2y}-8=0\] Here, \[a=1,b=2,h=\sqrt{2},g=2,\] \[f=2\sqrt{2},c=-8\] Since, the lines are parallel \[\therefore \]Distance between them is                 \[d=2\sqrt{\frac{{{g}^{2}}-ac}{a(a+b)}}\] \[\Rightarrow \]               \[d=2\sqrt{\frac{4+8}{1(3)}}=2\sqrt{\frac{12}{3}}=4\]


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