CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    An aqueous solution of glucose is 20% in strength. The volume in which 1g-mole of it is dissolved will be:

    A)  9 L                         

    B)         1.8 L

    C)  8 L                         

    D)         0.9 L

    E)  10 L

    Correct Answer: D

    Solution :

    \[\because \]20 g glucose is dissolved in 100 mL solution. \[\therefore \]1 g glucose is dissolved in\[\frac{100}{20}\]mL and 180 g (i.e., 1 g-mol) glucose is dissolved in                 \[=\frac{100}{20}\times 180\]                 \[=900\,mL\] \[=0.9\text{ }L\]


You need to login to perform this action.
You will be redirected in 3 sec spinner