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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v, perpendicular to one of its sides. A magnetic field of induction B, constant in space and time and pointing perpendicularly into the plane of the square, exists every where in space. The current induced in the loop is:

    A) \[BLv/R\] in the clockwise direction

    B) \[BLv/R\] in the anticlockwise direction

    C) \[2BLv/R\] in the clockwise direction

    D) \[2BLv/R\]in the anticlockwise direction

    E)  zero

    Correct Answer: E

    Solution :

    From Faradays law of electromagnetic induction, emf is induced with changing magnetic flux, but in this case since, magnetic field is pointing perpendicularly hence, magnetic flux does not change, hence current in the loop is zero.


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