question_answer

The emf of a Daniell cell at 298 K is\[{{E}_{1}}\] \[Zn/ZnS{{O}_{4}}(0.01\text{ }M)||CuS{{O}_{4}}\text{(1}\text{.0}\,\text{M) }\!\!|\!\!\text{  }Cu\] When the concentration of\[ZnS{{O}_{4}}\]is 1.0 M and that of\[CuS{{O}_{4}}\]is 0.01 M. The emf changed to \[{{E}_{2}}\]. What is the relation between\[{{E}_{1}}\]and\[{{E}_{2}}\]?

A)  \[{{E}_{1}}={{E}_{2}}\]                 

B)         \[{{E}_{2}}=0\ne {{E}_{1}}\]

C)  \[{{E}_{1}}>{{E}_{2}}\]                 

D)         \[{{E}_{1}}<{{E}_{2}}\]

E)  none of these