A) \[Q>R>P>S\]
B) \[R>Q>S>P\]
C) \[N{{a}_{2}}Si{{O}_{3}}\]
D) \[{{F}_{2}}\]
Correct Answer: C
Solution :
Lower the bond strength of \[0.2M\] bond. higher is the reactivity. Order of bond strength, \[N{{H}_{3}}\] Therefore, order of reactivity is \[N{{H}_{4}}Cl\]
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