A) 10 cm
B) 5cm
C) 20 cm
D) 15 cm
Correct Answer: B
Solution :
For objective (convex) lens \[\frac{2{{\eta }^{2}}}{g{{a}^{2}}}\] Here, \[\frac{{{\eta }^{2}}}{g{{a}^{2}}}\] \[\frac{{{\eta }^{2}}}{2g{{a}^{2}}}\] \[\frac{{{\eta }^{2}}}{4g{{a}^{2}}}\] \[{{t}_{1}}\] \[{{t}_{2}}\] \[2g({{t}_{1}}+{{t}_{2}})\] \[\frac{g}{4}{{({{t}_{1}}+{{t}_{2}})}^{2}}\] \[g/4({{t}_{1}}{{t}_{2}})\] Magnification \[2g{{\left( \frac{{{t}_{1}}+{{t}_{2}}}{4} \right)}^{2}}\] \[R/4\] \[R/2\] \[R/8\] \[\left\{ \frac{{{(1+e)}^{2}}}{1+{{e}^{2}}} \right\}\sqrt{\frac{gh}{2}}\]
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