A) \[\frac{{{\gamma }_{1}}-{{\gamma }_{2}}}{3}+\frac{\alpha }{3}\]
B) \[\frac{{{\gamma }_{1}}-{{\gamma }_{2}}}{2}+\alpha \]
C) \[\frac{{{\gamma }_{1}}-{{\gamma }_{2}}}{3}+3\alpha \]
D) \[\frac{{{\gamma }_{1}}-{{\gamma }_{2}}}{3}+\alpha \]
Correct Answer: B
Solution :
As, Power P = .FV = constant \[\Rightarrow \] \[F=\frac{P}{V}\] or, \[F\propto \frac{1}{V}\] as \[V\uparrow .F\downarrow \] When net force on block becomes zero, i.e. its maximum velocity \[P=({{\mu }_{mg}}){{v}_{\max }}={{v}_{\max }}=\frac{P}{\mu mg}\]
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