BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    If elements with principal quantum numbers n > 4 were not allowed in nature, then the number of possible elements would be     

    A)  \[1\text{ }km/h\]                                           

    B)  \[\text{3 }km/h\]             

    C)  \[\text{4 }km/h\]                                           

    D)  \[\text{5 }km/h\]              

    Correct Answer: B

    Solution :

                    If all the elements having n > 4 are removed the number of elements that will be present in the periodic table and calculated as n = 1 represent K shell and the number of elements having K shall = 2. n=2 represent L shell and the number of elements having L shell = 8. n = 3 represent M shell and the number of elements having M shell =18. n=4 represent N shell and the number of elements having N shell = 32. So, the total number of elements having n < 5 are \[2+8+18+32=60\]


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