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BVP Medical BVP Medical Solved Paper-2013

  • question_answer
    In an L-C-R circuit, capacitance is changed from C to 2 C. For the resonant frequency to remain unchanged, the inductance should be changed from L to

    A)  \[\frac{L}{4}\]                                  

    B)  \[\propto \text{x}\]

    C)  \[\propto {{\text{x}}^{2}}\]                       

    D)  \[\propto {{\text{x}}^{1/2}}\]

    Correct Answer: C

    Solution :

                    In the condition of resonance \[kg-{{m}^{-3}}\] \[0.0123\] Since, resonant frequency remains unchanged \[0.123\] = constant \[1.23~~\] = constant \[1.32\] \[k=200J{{m}^{-1}}-{{K}^{-2}}\] \[{{20}^{o}}C\]


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