A) \[\frac{L}{4}\]
B) \[\propto \text{x}\]
C) \[\propto {{\text{x}}^{2}}\]
D) \[\propto {{\text{x}}^{1/2}}\]
Correct Answer: A
Solution :
\[{{R}_{1}}=10+10+10=30\Omega \] \[{{R}_{3}}=20+20=40\Omega \] \[\frac{1}{{{R}_{eq}}}=\frac{1}{30}+\frac{1}{20}+\frac{1}{40}=\frac{4+6+3}{120}=\frac{13}{120}\] \[{{R}_{eq}}=\frac{120}{13}=9.23\Omega \]
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