A) \[_{1}^{3}H\]
B) \[_{6}^{14}C\]
C) \[_{19}^{40}K\]
D) All of these
Correct Answer: D
Solution :
\[_{1}^{3}H\xrightarrow{{}}_{2}^{3}He+\beta \] \[_{6}^{14}C\xrightarrow{{}}_{7}^{14}N+\beta \] \[_{19}^{40}K\xrightarrow{{}}_{20}^{40}Ca+\beta \]
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