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BVP Medical BVP Medical Solved Paper-2012

  • question_answer
    A particle executes SHM, its time period is 16 s. If its passes through the centre of   oscillation then its velocity is 2 m/s at time  2 s. The amplitude will be                  

    A)  \[0.81\]                              

    B)  \[0.42\]

    C)  \[{{r}_{A}}\]                                     

    D)  \[{{r}_{B}}\]

    Correct Answer: A

    Solution :

                    Given:  \[\frac{v(n-1)}{n}\] \[\frac{v(n+1)}{n}\] \[\frac{2v(n+1)}{n}\]                 \[F=q(v\times B)\]          \[[ML{{T}^{-1}}A]\]


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