A) acetic acid
B) saccharic acid
C) glyceraldehyde
D) gluconic acid
Correct Answer: D
Solution :
\[\underset{glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}+[O]}}\,\xrightarrow{B{{r}_{2}}/{{H}_{2}}O}\] \[C{{H}_{2}}OH.\underset{gluconic\,acid}{\mathop{{{(CHOH)}_{2}}}}\,COOH\]
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