BVP Medical BVP Medical Solved Paper-2007

  • question_answer
    Work done during isothermal expansion of one mole of an ideal gas from 10 atm to 1 atm at 300 K is

    A)  \[4938.8\text{ }J\]

    B)  \[4138.8\text{ }J\]

    C)  \[5744.1\text{ }J\]         

    D)  \[6257.2\text{ }J\]

    Correct Answer: C

    Solution :

                    Key Idea: For calculating work done during isothermal expansion of ideal gas we use the formula, \[W=2.303\text{ }nRT\text{ }log\text{ }\frac{{{P}_{2}}}{{{P}_{1}}}\] W = work done, \[n=1\], \[T=300K,\] \[{{P}_{2}}=1\] atm, \[{{P}_{1}}=10\] atm \[W=2.303\text{ }nRT\text{ }log\text{ }\frac{{{P}_{2}}}{{{P}_{1}}}\] \[=2.303\times 1\times 8.314\times 300\times \log \frac{1}{10}\] \[=5744.1J\]


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