A) 4 : 1
B) 1 : 4
C) 2 : 1
D) 1 : 2
Correct Answer: B
Solution :
The formula for terminal velocity is given by \[\upsilon =\frac{2}{9}{{r}^{2}}\frac{[g(\rho -\sigma )]}{\eta }\] \[\eta \]= Coefficient of viscosity So, \[\upsilon \propto {{r}^{2}}\] Hence, \[\frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}\]You need to login to perform this action.
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