A) \[{{n}^{3}}\]
B) 2 s
C) \[\frac{1}{n}\]
D) \[{{10}^{7}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
The time period of oscillation of magnet \[T\propto \frac{\sqrt{I}}{H}\] Therefore, \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{\sqrt{{{H}_{2}}}}{{{H}_{1}}}\] or \[\frac{1}{{{n}^{2}}}\] Here: \[{{n}^{3}}\] \[\frac{1}{n}\] So, \[{{10}^{7}}N/{{m}^{2}}\] or \[2.5\times {{10}^{6}}N/{{m}^{2}}\] or \[{{s}^{2}}\]
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