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BVP Medical BVP Medical Solved Paper-2002

  • question_answer
    Two strings of the same material and of same length have their tension in the ratio 4 :1 and their radii in the ratio 2:1. Then the ratio of their fundamental frequencies will be:

    A)  1                                            

    B) 0.5

    C) 4                                             

    D) 4

    Correct Answer: A

    Solution :

                    Frequency \[n=2\pi \sqrt{\frac{T}{m}}\] \[n=2\pi \sqrt{\frac{T}{\pi {{r}^{2}}l\rho }}\] \[n=2\pi \sqrt{\frac{T}{\pi {{r}^{2}}l\rho }}\] \[n\propto \sqrt{\frac{T}{r}}\] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\sqrt{\frac{{{T}_{1}}}{{{T}_{2}}}}\frac{{{r}_{2}}}{{{r}_{1}}}\] \[=\sqrt{\frac{4}{1}}\times \frac{1}{2}\] \[=\frac{2}{1}\times \frac{1}{2}=1\]


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