A) \[6\times {{10}^{-10}}m\]
B) \[6.6\times {{10}^{-10}}m\]
C) \[6\times {{10}^{-34}}m\]
D) \[6.6\times {{10}^{-34}}m\]
Correct Answer: D
Solution :
de Broglie wavelength \[\lambda =\frac{h}{m\upsilon }\] \[=\frac{6.6\times {{10}^{-34}}}{1\times 1}=6.6\times {{10}^{-34}}m\]
You need to login to perform this action.
You will be redirected in
3 sec
