A) \[0.5\text{ }mol\]
B) \[1.0\text{ }mol\]
C) \[1.5\text{ }mol~\]
D) \[2.0\text{ }mol\]
Correct Answer: A
Solution :
Since 0.5 moles of \[BaC{{l}_{2}}\] react with 0.5 mole of \[{{H}_{2}}S{{O}_{4}}\]. \[BaC{{l}_{2}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}BaS{{O}_{4}}+2HCl\] Thus, maximum amount of \[BaS{{O}_{4}}\] precipitated is 0.5 mole.
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