A) \[\frac{g}{3}\]
B) \[\frac{g}{6}\]
C) \[\frac{g}{2}\]
D) \[\frac{g}{9}\]
Correct Answer: A
Solution :
Suppose T is the tension in the string then the downward force will be \[Mg-T\] When a is downward acceleration then according to Newtons second law \[Mg-T=ma\] Here, \[{{T}_{\min }}=\frac{2}{3}mg\]then \[a={{a}_{\min }}\] \[mg-\frac{2}{3}mg=m{{a}_{\min }}\] So, \[{{a}_{\min }}g-\frac{2}{3}g=\frac{1}{3}g=\frac{8}{3}\]
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