A) 10 \[\overset{0}{\mathop{A}}\,\]
B) 1\[\overset{0}{\mathop{A}}\,\]
C) 0.1\[\overset{0}{\mathop{A}}\,\]
D) 0.01\[\overset{0}{\mathop{A}}\,\]
Correct Answer: C
Solution :
Using the relation, \[n=\frac{\upsilon }{\upsilon +{{\upsilon }_{s}}}\times n\] or \[\frac{c}{\lambda }=\frac{\upsilon }{\upsilon +{{\upsilon }_{s}}}\times \frac{c}{\lambda }\] or \[\lambda =\frac{\upsilon +{{\upsilon }_{s}}}{\upsilon }\times \lambda =\lambda +\frac{{{\upsilon }_{s}}}{\upsilon }\times \lambda \] Change in wavelength is \[\lambda -\lambda =\frac{{{\upsilon }_{s}}}{\upsilon }\times \lambda \] \[=\frac{6\times {{10}^{3}}\times 5000\times {{10}^{-10}}}{3\times {{10}^{8}}}=0.1\overset{\text{o}}{\mathop{\text{A}}}\,\]
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