A) \[6.08\times {{10}^{14}}\,cycke/s\]
B) \[4\times {{10}^{11}}\,cycke/s\]
C) \[6.5\times {{10}^{4}}\,cycke/s\]
D) \[6.6\times {{10}^{24}}\,cycke/s\]
Correct Answer: A
Solution :
Work function is \[\phi =hv\] or \[v=\frac{\phi }{h}\] ?..(i) (Here, \[\phi =2.51eV=2.51\times 1.6\times {{10}^{-19}}J\] h = Plancks constant \[=6.6\times {{10}^{-34}}Js\]) Hence, from equation (i) threshold frequency is \[v=\frac{2.51\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}\] \[=6.08\times {{10}^{14}}cycle/s\]
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