A) \[\frac{1}{d}\]
B) \[\frac{1}{{{d}^{3}}}\]
C) \[\frac{1}{{{d}^{3/2}}}\]
D) \[\frac{1}{{{d}^{2}}}\]
Correct Answer: B
Solution :
Magnetic field due to small magnet is \[{{B}_{axil}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{d}^{3}}}\] Also, \[B=\frac{{{\mu }_{0}}M(3co{{s}^{2}}\theta +1)}{4\pi \times {{d}^{3}}}\] \[{{B}_{equator}}=\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{d}^{3}}}\] So, \[B\propto \frac{1}{{{d}^{3}}}\] So, it is clear that \[B\propto \frac{1}{{{d}^{3}}}\]
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