BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    A small solid sphere rolls down without slipping a \[30{}^\circ \] inclined plane. Its acceleration is \[(g=10\text{ }m/{{s}^{2}})\]:

    A) \[\frac{3}{2}m/{{s}^{2}}\]                            

    B) \[\frac{9}{15}m/{{s}^{2}}\]         

    C) \[\frac{3}{25}m/{{s}^{2}}\]                         

    D) \[\frac{25}{7}m/{{s}^{2}}\]

    Correct Answer: D

    Solution :

                                                                     The relation for acceleration is given by as    \[a=\frac{g\,\,\sin \theta }{1+\frac{{{K}^{2}}}{{{R}^{2}}}}\] For sphere   \[\frac{{{K}^{2}}}{{{R}^{2}}}=\frac{2}{5}\] So,  \[\frac{{{K}^{2}}}{{{R}^{2}}}=\frac{2}{5}\] \[=\frac{25}{7}m/{{s}^{2}}\]


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