A) 7 km/s
B) 3.5 km/s
C) 5.2 km/s
D) 9.4 km/s
Correct Answer: B
Solution :
From the formula, the orbital velocity is \[{{\upsilon }_{0}}=\frac{\sqrt{GM}}{R}=7km/\sec \] ?..(1) If the radius of the orbit is four times that of the earth, then we have \[\upsilon _{0}^{}=\frac{\sqrt{GM}}{4R}\] ...(2) Now from equation (1) and (2) we get \[\frac{7}{\upsilon _{0}^{}}=\frac{\sqrt{GM/R}}{\sqrt{GM/4R}}=\frac{2}{1}\] So, \[\upsilon _{0}^{}=\frac{7}{2}=3.5km/s\]
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