A) 200 \[\mu C\]
B) 150\[\mu C\]
C) 300\[\mu C\]
D) 400\[\mu C\]
Correct Answer: A
Solution :
Three capacitors are given \[{{C}_{1}}=3\mu F,\,{{C}_{2}}=10\mu F,\,{{C}_{3}}=15\mu F\] Applied potential is \[=100V\] When the capacitance \[{{C}_{1}},{{C}_{2}}\] and \[{{C}_{3}}\] are connected in series then their equivalent capacitance is \[\frac{1}{{{C}_{S}}}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}+\frac{1}{{{C}_{3}}}=\frac{1}{3}+\frac{1}{10}+\frac{1}{15}=\frac{1}{2}\] \[{{C}_{S}}=2C\] Hence the charge on \[15\mu F\]capacitor is \[q=2\times 100=200\mu C\]
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