A) 0.02 kg \[{{m}^{2}}\]
B) 1.5 kg \[{{m}^{2}}\]
C) 0.8 kg \[{{m}^{2}}\]
D) 0.2 kg \[{{m}^{2}}\]
Correct Answer: D
Solution :
Here, mass \[M=0.4\text{ }kg\] and radius \[R=100\text{ }cm=1\text{ }m\] The moment of inertia of the disc about an axis perpendicular to the plane of the disc and passing through its centre is given by \[=\frac{1}{2}M{{R}^{2}}=\frac{1}{2}\times 0.4\times 1=0.2kg\,{{m}^{2}}\]
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