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BVP Medical BVP Medical Solved Paper-2000

  • question_answer
    In a neon discharge tube \[2.9\times {{10}^{18}}\,N{{e}^{+}}\] ions move to the right each second while\[1.2\times {{10}^{18}}\] electrons move to the left per second. Electron charge is\[1.6\times {{10}^{-19}}\]. The current in the discharge tube is:

    A)  zero                                     

    B)  0.66 A towards left

    C)  1A towards right I

    D)  0.66A towards right

    Correct Answer: D

    Solution :

    Net flow of charge per second is given by \[=(2.9\times {{10}^{18}}+1.2\times {{10}^{18}})\times e\] \[=4.1\times {{10}^{18}}\times 1.6\times {{10}^{-19}}=0.656A\] \[\approx \]  \[0.66A\] From this we conclude that the direction of current will be towards right as positive carriers are moving right wards.


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