A) 1 carbon atom less than amide
B) 1 carbon atom more than amide
C) 1 hydrogen atom less than amide
D) 1 hydrogen atom more than amide
Correct Answer: A
Solution :
\[RCON{{H}_{2}}+B{{r}_{2}}+4KOH\xrightarrow[{}]{{}}\] \[RN{{H}_{2}}+2KBr+{{K}_{2}}C{{O}_{3}}\] \[\because \]1 C of amide is removed in form of \[{{K}_{2}}C{{O}_{3}}\] \[\therefore \]amine formed has one C atom less than amide.
You need to login to perform this action.
You will be redirected in
3 sec
