A) \[{{C}_{2}}{{H}_{4}}\]
B) \[CH{{ }_{3}}OH\]
C) \[C{{H}_{3}}Br\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: D
Solution :
\[\underset{Methyl\,bromide}{\mathop{C{{H}_{3}}Br+{{H}_{2}}}}\,\xrightarrow{LiA{{H}_{4}}}\underset{Methane}{\mathop{C{{H}_{4}}}}\,+HBr\] \[\underset{Methyl\,bromide}{\mathop{2C{{H}_{3}}Br+Na}}\,\xrightarrow{{}}\underset{Ethane}{\mathop{{{C}_{2}}{{H}_{6}}}}\,+2NaBr\]
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