A) \[CaC{{O}_{3}}\]
B) \[NaOH\]
C) \[KOH\]
D) \[MgC{{O}_{3}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}+3{{I}_{2}}+4NaOH\xrightarrow[{}]{{}}\] \[\underset{idoform}{\mathop{CH{{I}_{3}}}}\,-\underset{sod.\,acetate}{\mathop{C{{H}_{3}}\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-ONa}}\,+\underset{sodium\,\,iodide}{\mathop{3NaI+3{{H}_{2}}O}}\,\] Therefore, acetone and iodine react in presence of\[NaOH\].
You need to login to perform this action.
You will be redirected in
3 sec
