A) \[12\times {{10}^{23}}\]
B) \[26\times {{10}^{23}}\]
C) \[34\times {{10}^{23}}\]
D) \[48\times {{10}^{23}}\]
Correct Answer: D
Solution :
Formula\[N{{a}_{4}}[Fe{{(CN)}_{6}}]\]sodium ferrocyanide suggests that it has four sodium atoms. \[Number\text{ }of\text{ }Na\text{ }atoms=no.\text{ }of\text{ }moles\times no.\text{ }of\] \[atoms\text{ }per\text{ }molecule\times Avogadro\text{ }number\] \[=2\times 4\times 6.023\times {{10}^{23}}\] \[=48\times {{10}^{23}}\]
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