A) 4938.8 J
B) 4138.8 J
C) 5744.1 J
D) 6257.2 J
Correct Answer: C
Solution :
Key Idea: For calculating work done during isothermal expansion of ideal gas we use the formula, \[W=2.303\text{ }nRT\text{ }log\frac{{{P}_{2}}}{{{P}_{1}}}\] W = work done, \[n=1,T=300K,{{P}_{2}}=1\,atm,\] \[{{P}_{1}}=10\text{ }atm\] \[W=2.303\text{ }nRT\text{ }\log \frac{{{P}_{2}}}{{{P}_{1}}}\] \[=2.303\times 1\times 8.314\times 300\times \log \frac{1}{10}\] \[=5744.1\text{ }J\]
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