A) 3600 \[\overset{\circ }{\mathop{\text{A}}}\,\]
B) 2400 \[\overset{\circ }{\mathop{\text{A}}}\,\]
C) 1800 \[\overset{\circ }{\mathop{\text{A}}}\,\]
D) 1200 \[\overset{\circ }{\mathop{\text{A}}}\,\]
Correct Answer: C
Solution :
The minimum energy required for the emission of photoelectron from a metal is called work function of that metal, \[W=\frac{hc}{\lambda }\] Where \[h\] is Planck?s constant, \[c\] is speed of light \[\lambda \] is wavelength. \[\Rightarrow \lambda =\frac{hc}{W}\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{6.825\times 1.6\times {{10}^{-19}}}\] \[=1.8\times {{10}^{-7}}\] \[=1800\times {{10}^{-10}}m\] \[=1800\]Å
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