A) \[{{f}_{R}}<{{f}_{G}}<{{f}_{V}}\]
B) \[{{f}_{V}}<{{f}_{G}}<{{f}_{R}}\]
C) \[{{f}_{G}}<{{f}_{R}}<{{f}_{V}}\]
D) \[{{f}_{G}}<{{f}_{V}}<{{f}_{R}}\]
Correct Answer: B
Solution :
From lens formula, we have \[\frac{1}{f}=\left( \mu -1 \right)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] \[\Rightarrow \] \[\frac{1}{f}\propto \,u\] Since, \[{{\mu }_{V}}>{{\mu }_{G}}>{{\mu }_{R}}\] Therefore, \[{{f}_{V}}>{{f}_{G}}>{{f}_{R}}.\]
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