A) \[8\times {{10}^{-3}}\,V\]
B) \[6\times {{10}^{-3}}\,V\]
C) \[4\times {{10}^{-3}}\,V\]
D) \[2\times {{10}^{-3}}\,V\]
Correct Answer: D
Solution :
From Faraday?s law of electromagnetic induction, when the magnetic flux through a circuit is changing an induced emf (e) is set up in the circuit whose magnitude is equal to the negative rate of change of magnetic flux \[\left( \phi \right)\] \[e=-\frac{d\phi }{dt}\] Given, \[d\phi =8\times {{10}^{-4}}\,Wb,\,dt=0.4\,s\] \[\Rightarrow \] \[e=-\frac{8\times {{10}^{-4}}}{0.4}\] \[=-2\times {{10}^{-3\,}}\,V\] Note: The direction of induced emf is such as to oppose the change that produced it.
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